in any case, both are wrong
it's more like 375 - 382 C.

these values must be for pure crystalline DMT, straight from the Speeter-Anthony method or something.

How can that be? How is it possible for DMT to vaporize in a VG/GVG if the VG/GVG doesn’t come close to that temp?

maybe impure DMT.
impure compounds have a lower boiling point

Not to belabor this, but are you saying that ultra-pure DMT would not vaporize in a VG/GVG? (Assuming the chamber temp. in a VG/GVG is between 300-400ºF as claimed by the manufacturer?)

yup

Boiling point 160 °C (320 °F) @ 0.6 Torr[1] also reported as 80 - 135 °C @ 0.03 Torr[2]
http://www.answers.com/topic/dimethyltryptamine

160 C at 0.6 torr is 375 C (707 F) at atmospheric pressure.

Maybe the manufacturers claim is optimistic or perhaps the claim comes from the fact that THC vaporizes at 315 °F. . . . I think a GVG does vapourize pure dmt, but at higher temperature than it vaporizes thc.

Yes, perhaps. But 382ºC is 720ºF !! I also find it hard to believe that miniscule quantities of impurities (some of which may have B.P.s higher than DMT) can lower the B.P. from 720ºF to somewhere around 400ºF.


Is it possible that DMT “evaporates” at a temperature significantly below its boiling point? Much like hot water below the boiling point will produce lots of steam? Is it possible that the DMT vapors we consume are from DMT that hasn’t reached its boiling point?

Has anyone ever put a sample of DMT in an oil bath at, let’s say 400ºF, to see what happens?

I think I’ve figured out the DMT boiling point conundrum: The reason that boiling points for DMT are always shown at reduced pressure is because DMT decomposes at temperatures below that of its extrapolated standard atmospheric pressure boiling point.

My guess is that DMT decomposes at a temperature below 382ºC. This is why you’ll never see a BP listed at that temperature. This value can be extrapolated from reduced pressure BPs, but it’s a “theoretical” BP, and not an actual BP.

A simple organic molecule that behaves similarly is sucrose. It melts, but never boils. It decomposes (caramelizes, then eventually carbonizes) before it ever reaches its boiling point.

So the vapors from DMT are not produced by boiling, but by evaporation at a temperature below the BP and ideally below the temperature at which DMT begins to decompose.

Does any of this make sense?

Sister thinks its very reasonable to assume that dmt will decompose at or below 382°C. Although its possible that it doesn't decompose immediately, which might give vapour a chance to form. Sister has also seen dmt char in a freebase pipe when too much heat was applied.

Be great to have one of those IR thermometers like Benzyme has and see exactly what is going on in a GVG.

Airflow in the pipe will of course assist vaporization.