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DMT Acetate and slaked lime reaction? Options
 
zimzimzimma
#1 Posted : 11/25/2012 11:20:50 AM
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Hi my fellow psychonauts, as a psychedelic and amateur chemist enthusiast I've made my first batch of DMT with a friend and tried it out yesterday. Boy what an experience. We are using the vinegar/lime extraction tek for extraction which works really well.
As a chemist enthusiast I am curious on how the reaction goes. I understand DMT tannate with vinegar makes DMT acetate, separating the two and leaving the hydrogen atom from the vinegar (acetic acid) binding to the tannate group. The next step involves slaked lime aka calcium hydroxide which converts the DMT acetate to freebase DMT. I have been looking for this reaction out of pure interest and to be able to calculate the exact amounts of material needed using the molecular weight and Avogadro's number.
I've been searching for a few hours (also here) but I haven't found a working example. My best guess is:

2 DMT-CH3COO + Ca(OH)2 + = Ca(CH3COO)2 + 2 DMT + O2

But I think I'm missing something here since I think the two OH- groups from the slaked lime do not dissociate that easily. But this is the only way I can get the reaction to balance out Sad If they don't the reaction would be

2 DMT-CH3COO + Ca(OH)2 + = Ca(CH3COO)2 + 2 DMT-OH

But that's not freebase DMT, it's psylocin. Can someone help me out? Wanted to post in the 'advanced chemistry' section but I'm forced to post here first, so... Smile
 

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Infundibulum
#2 Posted : 11/25/2012 2:27:04 PM

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the simple way to write the conversion reaction is:

2 CH3COONH-DMT + Ca(OH)2 = (CH3COO)2Ca + 2DMT-N +2H2O

(given that dmt freebase is denoted as"DMT-N", N being the tertiary basic amine and the ionised form as "DMT-NH"Pleased

Obviously to get freebase you need more base than stoichiometrically needed for the reaction to keep dmt freebase from ionising.

Your mistake when you were trying to figure the reaction was to denote dmt acetate as "DMT-CH3COO", which misses one hydrogen out of the whole salt formula. You should had written it as "DMT-CH3COOH" or, for better clarity so as to denote the reacting groups, "CH3COONH-DMT" (also, DMT - OH is by no means psilocin!)



Need to calculate between salts and freebases? Click here!
Need to calculate freebase or salt percentage at a given pH? Click here!

 
zimzimzimma
#3 Posted : 11/29/2012 8:36:54 PM
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Aight, makes sense. I can sleep well now... tnx a bunch!
 
 
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